Tim Rollston's Splitting a Quadratic Using de Casteljau's Algorithm (5 of 5) - OpenLearning


Question 1

The de Casteljau Bezier curve C has parametric equation

Correct!

  • Selected: (1-t)^2 P_0 + 2(1-t)t P_1 + t^2 P_2
  • [1 + 2t + t^2, 1 + 4t - 3t^2]
  • Selected: [1 + 4t + t^2, 1 + 8t - 7t^2]
  • [cos(t), sin(t^2)]
  • (1-t)^2 P_1 + 2(1-t)t P_2 + t^2 P_0
  • [1 + 3t + 2t^2, 1 + 4t - 3t^2]

Question 2

When t=0.5, what are the co-ordinates of the point R_0 on the curve?

Correct!

  • [3 1/3, 3 1/2]
  • [Pi, Pi]
  • Selected: [3 1/4, 3 1/4]
  • [3.5, 3.3]

Question 3

Use de Casteljau's algorithm to split the curve C into a left curve C_1 and right  curve C_2. What are the control points of C_1?

Correct!

  • Selected: P_0
  • P_1
  • P_2
  • Selected: Q_0
  • Q_1
  • Selected: R_0

Question 4

For a quadratic de Casteljau Bezier curve, there is one control point which is not on the curve. <br><br>What are the co-ordinates of this control point for C_1? Give your answer in the form [x,y].

Correct!

[2,3]


Question 5

Here is the last question: a bit of a challenge! <br><br>The original de Casteljau Bezier curve is a parabola, so it should have an equation in x and y. It is:

Correct!

  • 49x²+14xy+y²-400x+120y+200=0
  • Selected: 49x²+14xy+y²-400x+128y+208=0
  • 49x²+14xy+y²-100x+128y+200=0
  • 48x²+14xy+y²-100x+128y+208=0

Result:

5/5

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